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© h.hofstede (h.hofstede@hogeland.nl) |
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| 1. | μS
= 5 • 73 = 365 σS = √5 • 18 normalcdf(400, 1099, 365, √5 • 18) = 0,1923 |
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| 2. | μS
= 80 + 55 = 135 σS 2 = 42 + 32 dus σS = 5 normalcdf(140, 1099, 135, 5) = 0,1587 |
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| 3. | a. | μS
= 40 + 30 = 70 σS2 = 82 + 52 = 89 dus σS = √89 normalcdf(0, 65, 70, √89) = 0,2981 |
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| b. | μS
= 100 • 70 = 7000 σS = 13 • √100 = 130 normalcdf(0, 650, 700, 130) = 0,3503 |
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| 4. | Dat zijn 60 dozen en
60 • 50 = 3000 pakjes μS = 60 • 1400 + 3000 • 500 = 1584000 σS2 = 60 • 1002 + 3000 • 202 = 1800000 dus σS =1341,64 normalcdf(1585000, 1099, 1584000, 1341.64) = 0,2280 |
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| 5. | a. | normalcdf(0, 11, 13,
1.5) = 0,0912 dat zijn 0,0912 • 800 = 73 studenten |
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| b. | 50 studenten is
50/800 = 0,0625% Y1 = normalcdf(0, X, 13, 1.5) Y2 = 0,0625 intersect geeft X = 10,7 ze lopen dus 10,7 seconden of minder |
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| c. | μS
= 10,3 + 10,5 + 19,5 + 10,6 = 41,9 σS2 = 0,42 + 0,22 + 0,52 + 0,62 = 0,81 dus σS = 0,9 normalcdf(0, 42, 41.9, 0.9) = 0,5442 |
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| 7. | a. | μS
= 15 • 2,14 = 32,1 σS = 0,04 • √15 normalcdf(32.5, 1099, 32.1, 0,04√15) = 0,0049 |
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| b. | μS
= 5 • 7,80 + 8 • 8,50 = 107 σS = 0,3 • √13 normalcdf(0, 105, 107, 0.3√13) = 0,0322 |
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| 8. | a. | normalcdf(5, 1099, 3.6, 0.7) = 0,0228 | |
| b. | μS
= 16 • 3.6 = 57,6 minuten σS = 0,7 • √16 = 2,8 minuten normalcdf(60, 1099, 57.6, 2.8) = 0,1957 |
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